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Determination of whether the following relations are reflexive, symmetric, and transitive: Relation R in the set N of natural numbers defined as R = {(x, y): y = x + 5 and x < 4} - Mathematics

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प्रश्न

determination of whether the following relations are reflexive, symmetric, and transitive:

Relation R in the set N of natural numbers defined as

R = {(x, y): y = x + 5 and x < 4}

बेरीज

उत्तर

R = {(x, y): y = x + 5 and x < 4} = {(1, 6), (2, 7), (3, 8)}

It is seen that (1, 1) ∉ R.

∴R is not reflexive.

(1, 6) ∈R

But,

(6, 1) ∉ R.

∴R is not symmetric.

Transitive

(1, 6) E Rand (6, 7) ∉ R, and (1, 7) ∉ R

∴ R is transitive.

Hence R is neither reflexive, nor symmetric but transitive.

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पाठ 1: Relations and Functions - Exercise 1.1 [पृष्ठ ५]

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एनसीईआरटी Mathematics [English] Class 12
पाठ 1 Relations and Functions
Exercise 1.1 | Q 1.2 | पृष्ठ ५

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