मराठी

Evaluate the following: 3 sin 37 ° cos 53 ° − 5 cosec 39 ° sec 51 ° + 4 tan 23 ° tan 37 ° tan 67 ° tan 53 ° cos 17 ° cos 67 ° cosec 73 ° cosec 23 ° Q - Mathematics

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प्रश्न

Evaluate the following: `(3sin37°)/(cos53°) - (5"cosec"39°)/(sec51°) + (4tan23° tan37° tan67° tan53°)/(cos17° cos67° "cosec"73° "cosec"23°)`

बेरीज

उत्तर

`(3sin37°)/(cos53°) - (5"cosec"39°)/(sec51°) + (4tan23° tan37° tan67° tan53°)/(cos17° cos67° "cosec"73° "cosec"23°)`

= `(3sin(90° - 53°))/(cos53°) - (5"cosec"(90° - 51°))/(sec51°) + (4tan(90° - 67°) tan(90° - 53°) xx 1/(cot67°) xx 1/(cot53°))/(cos(90° - 73°) cos(90° - 23°) xx 1/(sin73°) xx 1/(sin23°)`

= `(3cos53°)/(cos53°) - (5sec51°)/(sec51°) + (4 cos67° cos53° xx 1/(cot67°) xx 1/cot53°)/(sin73° sin23° xx 1/(sin73°) xx 1/sin23°)`

= 3 - 5 + 4
= 2.

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Trigonometric Equation Problem and Solution
  या प्रश्नात किंवा उत्तरात काही त्रुटी आहे का?
पाठ 27: Trigonometrical Ratios of Standard Angles - Exercise 27.3

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फ्रँक Mathematics [English] Class 9 ICSE
पाठ 27 Trigonometrical Ratios of Standard Angles
Exercise 27.3 | Q 5.06
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