मराठी

Evaluate the following: tan(78° + θ) + cosec(42° + θ) - cot(12° - θ) - sec(48° - θ) - Mathematics

Advertisements
Advertisements

प्रश्न

Evaluate the following: tan(78° + θ) + cosec(42° + θ) - cot(12° - θ) - sec(48° - θ)

बेरीज

उत्तर

tan(78° + θ) + cosec(42° + θ) - cot(12° - θ) - sec(48° - θ)
= tan[90° - (12° - θ)] + cosec[90° - (48° - θ)] - cot(12° - θ) - sec(48° - θ)
= cot(12° - θ) + sec(48° - θ)] - cot(12° - θ) - sec(48° - θ)
= 0.

shaalaa.com
Trigonometric Equation Problem and Solution
  या प्रश्नात किंवा उत्तरात काही त्रुटी आहे का?
पाठ 27: Trigonometrical Ratios of Standard Angles - Exercise 27.3

APPEARS IN

फ्रँक Mathematics [English] Class 9 ICSE
पाठ 27 Trigonometrical Ratios of Standard Angles
Exercise 27.3 | Q 5.05
Share
Notifications

Englishहिंदीमराठी


      Forgot password?
Use app×