Advertisements
Advertisements
प्रश्न
Evaluate the following: sin35° sin45° sec55° sec45°
उत्तर
sin35° sin45° sec55° sec45°
= `sin(90° - 55°) xx (1)/sqrt(2) xx (1)/(cos55°) xx sqrt(2)`
= `cos55° xx (1)/(cos55°) xx (1)/sqrt(2) xx sqrt(2)`
= 1.
APPEARS IN
संबंधित प्रश्न
If 4 cos2 x = 3 and x is an acute angle;
find the value of :
(i) x
(ii) cos2 x + cot2 x
(iii) cos 3x (iv) sin 2x
Solve for x : cos (2x - 30°) = 0
Solve for 'θ': cot2(θ - 5)° = 3
If θ = 15°, find the value of: cos3θ - sin6θ + 3sin(5θ + 15°) - 2 tan23θ
If θ < 90°, find the value of: `tan^2θ - (1)/cos^2θ`
If tan x° = `(5)/(12) . tan y° = (3)/(4)` and AB = 48m; find the length CD.
In right-angled triangle ABC; ∠B = 90°. Find the magnitude of angle A, if:
a. AB is `sqrt(3)` times of BC.
B. BC is `sqrt(3)` times of BC.
Evaluate the following: `(sec34°)/("cosec"56°)`
Express each of the following in terms of trigonometric ratios of angles between 0° and 45°: tan77° - cot63° + sin57°
Express each of the following in terms of trigonometric ratios of angles between 0° and 45°: cos84° + cosec69° - cot68°