Advertisements
Advertisements
प्रश्न
Find the diameter of the circle if the length of a chord is 3.2 cm and itd distance from the centre is 1.2 cm.
उत्तर
AD = DB = 1.6 cm (Perpendicular from centre to a chord bisects the chord)
In right Δ ODA ,
By Pythagoras theorem , OA2 = OD2 + AD2
= 1.62 + 1.22
= 2.56 + 1.44
OA2 = 4
OA = 2 cm
Diameter (AP) = 2 (OA) = 2 (1) = 4 cm
APPEARS IN
संबंधित प्रश्न
Two tangents TP and TQ are drawn to a circle with centre O from an external point T. Prove that ∠PTQ = 2∠OPQ.
Prove that the line segment joining the point of contact of two parallel tangents to a circle is a diameter of the circle.
From a point P, two tangents PA and PB are drawn to a circle with center O. If OP =
diameter of the circle shows that ΔAPB is equilateral.
Fill in the blank
A continuous piece of a circle is ............... of the circle
If the length of a chord of a circle is 16 cm and is at a distance of 15 cm from the centre of the circle, then the radius of the circle is
In a circle, AB and CD are two parallel chords with centre O and radius 10 cm such that AB = 16 cm and CD = 12 cm determine the distance between the two chords?
Three circles touch each other externally. The distance between their centres is 5 cm, 6 cm, and 7 cm. Find the radii of the circles.
If AB = 12 cm, BC = 16 cm and AB is perpendicular to BC, then the radius of the circle passing through the points A, B and C is ______.
In the following figure, O is the centre of the circle, BD = OD and CD ⊥ AB. Find ∠CAB.
In the given figure, O is the centre of the circle. If ∠ AOB = 145°, then find the value of x.
