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Question
Find the diameter of the circle if the length of a chord is 3.2 cm and itd distance from the centre is 1.2 cm.
Solution
AD = DB = 1.6 cm (Perpendicular from centre to a chord bisects the chord)
In right Δ ODA ,
By Pythagoras theorem , OA2 = OD2 + AD2
= 1.62 + 1.22
= 2.56 + 1.44
OA2 = 4
OA = 2 cm
Diameter (AP) = 2 (OA) = 2 (1) = 4 cm
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