मराठी

Find the Equation of the Circle Which Passes Through the Origin and Cuts off Chords of Lengths 4 and 6 on the Positive Side of the X-axis and Y-axis Respectively. - Mathematics

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प्रश्न

Find the equation of the circle which passes through the origin and cuts off chords of lengths 4 and 6 on the positive side of the x-axis and y-axis respectively.

उत्तर

According to the question, the circle passes through the origin.
Let the equation of the circle be

\[x^2 + y^2 - 2hx - 2ky = 0\]

The circle cuts off chords of lengths 4 and 6 on the positive sides of the x-axis and the y-axis, respectively.

∴ Centre = \[\left( \frac{4}{2}, \frac{6}{2} \right) = \left( 2, 3 \right) = \left( h, k \right)\]

\[\Rightarrow h = 2, k = 3\]

∴ Required equation: \[x^2 + y^2 + 2\left( - 2 \right)x + 2\left( - 3 \right)y = 0\]

\[\Rightarrow x^2 + y^2 - 4x - 6y = 0\]
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Circle - Standard Equation of a Circle
  या प्रश्नात किंवा उत्तरात काही त्रुटी आहे का?
पाठ 24: The circle - Exercise 24.2 [पृष्ठ ३२]

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आरडी शर्मा Mathematics [English] Class 11
पाठ 24 The circle
Exercise 24.2 | Q 10 | पृष्ठ ३२

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