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प्रश्न
Find the intercepts cut off by the plane 2x + y – z = 5.
Find the sum of the intercepts cut off by the plane \[2x + y - z = 5,\]on the coordinate axes.
उत्तर
2x + y – z = 5 ...(1)
Dividing both sides of equation (1) by 5, we obtain
Thus, the intercepts cut off by the plane are `5/2, 5 and -5`
∴ Required sum of intercepts = \[\frac{5}{2} + 5 + \left( - 5 \right) = \frac{5}{2}\] .
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