Advertisements
Advertisements
प्रश्न
Find the mean, variance and standard deviation for the data:
6, 7, 10, 12, 13, 4, 8, 12.
उत्तर
6,7,10,12,13,4,8,12
\[\text{ Mean } = \frac{6 + 7 + 10 + 12 + 13 + 4 + 8 + 12}{8}\]
\[ = \frac{72}{8}\]
\[ = 9\]
\[x_i\]
|
\[\left( x_i - X \right) = \left( x_i - 9 \right)\]
|
|
---|---|---|
6 | -3 | 9 |
7 | -2 | 4 |
10 | 1 | 1 |
12 | 3 | 9 |
13 | 4 | 16 |
4 |
|
25 |
8 |
|
1 |
12 | 3 | 9 |
|
n = 8
\[\therefore \text{ Variance } \left( X \right) = \frac{\sum^8_{i = 1} \left( x_i - X \right)^2}{n}\]
\[ = \frac{74}{8} \]
\[ = 9 . 25\]
\[\text{ Standard deviation }= \sqrt{\text{Variance} \left( X \right)} \]
\[ = \sqrt{9 . 25} \]
\[ = 3 . 04\]
APPEARS IN
संबंधित प्रश्न
Find the mean and variance for the data.
6, 7, 10, 12, 13, 4, 8, 12
Find the mean and variance for the first n natural numbers.
Find the mean and variance for the data.
xi | 6 | 10 | 14 | 18 | 24 | 28 | 30 |
fi | 2 | 4 | 7 | 12 | 8 | 4 | 3 |
The mean and standard deviation of six observations are 8 and 4, respectively. If each observation is multiplied by 3, find the new mean and new standard deviation of the resulting observations
Given that `barx` is the mean and σ2 is the variance of n observations x1, x2, …,xn. Prove that the mean and variance of the observations ax1, ax2, ax3, …,axn are `abarx` and a2 σ2, respectively (a ≠ 0).
The mean and standard deviation of 20 observations are found to be 10 and 2, respectively. On rechecking, it was found that an observation 8 was incorrect. Calculate the correct mean and standard deviation in each of the following cases:
- If wrong item is omitted.
- If it is replaced by 12.
Find the mean, variance and standard deviation for the data:
227, 235, 255, 269, 292, 299, 312, 321, 333, 348.
Find the mean, variance and standard deviation for the data 15, 22, 27, 11, 9, 21, 14, 9.
The variance of 20 observations is 5. If each observation is multiplied by 2, find the variance of the resulting observations.
The mean and variance of 8 observations are 9 and 9.25 respectively. If six of the observations are 6, 7, 10, 12, 12 and 13, find the remaining two observations.
For a group of 200 candidates, the mean and standard deviations of scores were found to be 40 and 15 respectively. Later on it was discovered that the scores of 43 and 35 were misread as 34 and 53 respectively. Find the correct mean and standard deviation.
The mean and standard deviation of a group of 100 observations were found to be 20 and 3 respectively. Later on it was found that three observations were incorrect, which were recorded as 21, 21 and 18. Find the mean and standard deviation if the incorrect observations were omitted.
Show that the two formulae for the standard deviation of ungrouped data
\[\sigma = \sqrt{\frac{1}{n} \sum \left( x_i - X \right)^2_{}}\] and
\[\sigma' = \sqrt{\frac{1}{n} \sum x_i^2 - X^2_{}}\] are equivalent, where \[X = \frac{1}{n}\sum_{} x_i\]
Find the standard deviation for the following distribution:
x : | 4.5 | 14.5 | 24.5 | 34.5 | 44.5 | 54.5 | 64.5 |
f : | 1 | 5 | 12 | 22 | 17 | 9 | 4 |
Calculate the mean and S.D. for the following data:
Expenditure in Rs: | 0-10 | 10-20 | 20-30 | 30-40 | 40-50 |
Frequency: | 14 | 13 | 27 | 21 | 15 |
Calculate the standard deviation for the following data:
Class: | 0-30 | 30-60 | 60-90 | 90-120 | 120-150 | 150-180 | 180-210 |
Frequency: | 9 | 17 | 43 | 82 | 81 | 44 | 24 |
Calculate the mean, median and standard deviation of the following distribution:
Class-interval: | 31-35 | 36-40 | 41-45 | 46-50 | 51-55 | 56-60 | 61-65 | 66-70 |
Frequency: | 2 | 3 | 8 | 12 | 16 | 5 | 2 | 3 |
Find the mean and variance of frequency distribution given below:
xi: | 1 ≤ x < 3 | 3 ≤ x < 5 | 5 ≤ x < 7 | 7 ≤ x < 10 |
fi: | 6 | 4 | 5 | 1 |
The weight of coffee in 70 jars is shown in the following table:
Weight (in grams): | 200–201 | 201–202 | 202–203 | 203–204 | 204–205 | 205–206 |
Frequency: | 13 | 27 | 18 | 10 | 1 | 1 |
Determine the variance and standard deviation of the above distribution.
Mean and standard deviation of 100 observations were found to be 40 and 10 respectively. If at the time of calculation two observations were wrongly taken as 30 and 70 in place of 3 and 27 respectively, find the correct standard deviation.
The means and standard deviations of heights ans weights of 50 students of a class are as follows:
Weights | Heights | |
Mean | 63.2 kg | 63.2 inch |
Standard deviation | 5.6 kg | 11.5 inch |
Which shows more variability, heights or weights?
Coefficient of variation of two distributions are 60% and 70% and their standard deviations are 21 and 16 respectively. What are their arithmetic means?
The mean and standard deviation of marks obtained by 50 students of a class in three subjects, mathematics, physics and chemistry are given below:
Subject | Mathematics | Physics | Chemistry |
Mean | 42 | 32 | 40.9 |
Standard Deviation | 12 | 15 | 20 |
Which of the three subjects shows the highest variability in marks and which shows the lowest?
From the data given below state which group is more variable, G1 or G2?
Marks | 10-20 | 20-30 | 30-40 | 40-50 | 50-60 | 60-70 | 70-80 |
Group G1 | 9 | 17 | 32 | 33 | 40 | 10 | 9 |
Group G2 | 10 | 20 | 30 | 25 | 43 | 15 | 7 |
If the sum of the squares of deviations for 10 observations taken from their mean is 2.5, then write the value of standard deviation.
Let a, b, c, d, e be the observations with mean m and standard deviation s. The standard deviation of the observations a + k, b + k, c + k, d + k, e + k is
The mean of 100 observations is 50 and their standard deviation is 5. The sum of all squares of all the observations is
Show that the two formulae for the standard deviation of ungrouped data.
`sigma = sqrt((x_i - barx)^2/n)` and `sigma`' = `sqrt((x^2_i)/n - barx^2)` are equivalent.
Life of bulbs produced by two factories A and B are given below:
Length of life (in hours) |
Factory A (Number of bulbs) |
Factory B (Number of bulbs) |
550 – 650 | 10 | 8 |
650 – 750 | 22 | 60 |
750 – 850 | 52 | 24 |
850 – 950 | 20 | 16 |
950 – 1050 | 16 | 12 |
120 | 120 |
The bulbs of which factory are more consistent from the point of view of length of life?
Find the standard deviation of the first n natural numbers.
The mean and standard deviation of a set of n1 observations are `barx_1` and s1, respectively while the mean and standard deviation of another set of n2 observations are `barx_2` and s2, respectively. Show that the standard deviation of the combined set of (n1 + n2) observations is given by
S.D. = `sqrt((n_1(s_1)^2 + n_2(s_2)^2)/(n_1 + n_2) + (n_1n_2 (barx_1 - barx_2)^2)/(n_1 + n_2)^2)`
Standard deviations for first 10 natural numbers is ______.
The standard deviation of a data is ______ of any change in orgin, but is ______ on the change of scale.
The standard deviation is ______to the mean deviation taken from the arithmetic mean.