मराठी

Find the Value Of: Log √ 27 + Log 8 + Log √ 1000 Log 120 - Mathematics

Advertisements
Advertisements

प्रश्न

Find the value of:

`("log"sqrt(27) + "log"8 + "log"sqrt(1000))/("log"120)`

बेरीज

उत्तर

`("log"sqrt(27) + "log"8 + "log"sqrt(1000))/("log"120)`

= `("log"(27)^(1/2) + "log"2^3 + "log"1000^(1/2))/("log"(3 xx 2^2 xx 10)`

= `("log"(3)^(3xx1/2) + "log"2^3 + "log"(10)^(3xx1/2))/("log"3 + "log2^2 + "log 10)`

= `(3/2"log"3 + 3"log"2 + 3/2"log"(10))/("log"3 + 2 "log"2 + "log"10)`

= `(3/2"log"3 + 3/2(2"log"2) + 3/2(1))/("log"3 + 2"log2 + 1)`

= `(3/2["log" 3 + 2"log" 2 + 1])/("log"3 + 2"log2 + 1)`

= `(3)/(2)`.

shaalaa.com
Expansion of Expressions with the Help of Laws of Logarithm
  या प्रश्नात किंवा उत्तरात काही त्रुटी आहे का?
पाठ 10: Logarithms - Exercise 10.2

APPEARS IN

फ्रँक Mathematics [English] Class 9 ICSE
पाठ 10 Logarithms
Exercise 10.2 | Q 32.2
Share
Notifications

Englishहिंदीमराठी


      Forgot password?
Use app×