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प्रश्न
If \[f\left( x \right) = \begin{cases}\frac{x^2 - 1}{x - 1}; for & x \neq 1 \\ 2 ; for & x = 1\end{cases}\] Find whether f(x) is continuous at x = 1.
उत्तर
Given:
\[f\left( x \right) = \binom{\frac{x^2 - 1}{x - 1}, if x \neq 1}{2, if x = 1}\]
We observe
(LHL at x = 1) =
(RHL at x = 1) =
Given:
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