Advertisements
Advertisements
प्रश्न
If O is the centre of the circle, find the value of x in the following figure
उत्तर
We have
∠ DBO = 40°
∠ DBC = 90°
⇒ ∠ DBO + ∠OBC = 90°
⇒ 40° + ∠OBC = 90°
⇒ ∠ OBC = 90° - 40° = 50°
By degree measure theorem
ÐAOC = 2ÐOBC
⇒ x = 2´ 50° = 100°
APPEARS IN
संबंधित प्रश्न
Given an arc of a circle, complete the circle.
If O is the centre of the circle, find the value of x in the following figure
If O is the centre of the circle, find the value of x in the following figures.
In the given figure, O is the centre of the circle, prove that ∠x = ∠y + ∠z.
Prove that the angle in a segment shorter than a semicircle is greater than a right angle.
In the given figure, two circles intersect at A and B. The centre of the smaller circle is Oand it lies on the circumference of the larger circle. If ∠APB = 70°, find ∠ACB.
In the given figure, AB is a diameter of the circle such that ∠A = 35° and ∠Q = 25°, find ∠PBR.
In the given figure, P and Q are centres of two circles intersecting at B and C. ACD is a straight line. Then, ∠BQD =
In the given figure, if O is the circumcentre of ∠ABC, then find the value of ∠OBC + ∠BAC.
The chord of a circle is equal to its radius. The angle subtended by this chord at the minor arc of the circle is
