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प्रश्न
In a non-leap year, the probability of having 53 tuesdays or 53 wednesdays is ______.
पर्याय
`1/7`
`2/7`
`3/7`
None of these
उत्तर
In a non-leap year, the probability of having 53 tuesdays or 53 wednesdays is `1/7`.
Explanation:
There are 365 days in a non-leap year and there are 7 days in a week
∴ 365 ÷ 7 = 52 weeks + 1 day
So, this day may be Tuesday or Wednesday.
So, the required probability = `1/7`.
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संबंधित प्रश्न
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| Assignment | ω1 | ω2 | ω3 | ω4 | ω5 | ω6 | ω7 |
| (a) | 0.1 | 0.01 | 0.05 | 0.03 | 0.01 | 0.2 | 0.6 |
| (b) | `1/7` | `1/7` | `1/7` | `1/7` | `1/7` | `1/7` | `1/7` |
| (c) | 0.1 | 0.2 | 0.3 | 0.4 | 0.5 | 0.6 | 0.7 |
| (d) | –0.1 | 0.2 | 0.3 | 0.4 | -0.2 | 0.1 | 0.3 |
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