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Question
In a non-leap year, the probability of having 53 tuesdays or 53 wednesdays is ______.
Options
`1/7`
`2/7`
`3/7`
None of these
Solution
In a non-leap year, the probability of having 53 tuesdays or 53 wednesdays is `1/7`.
Explanation:
There are 365 days in a non-leap year and there are 7 days in a week
∴ 365 ÷ 7 = 52 weeks + 1 day
So, this day may be Tuesday or Wednesday.
So, the required probability = `1/7`.
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