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Question
Two unbiased dice are thrown. Find the probability that the total of the numbers on the dice is greater than 10.
Solution
If two dices are thrown simultaneously, then all the possible outcomes = 62 = 36
∴ Total number of possible outcome, n(S) = 36
Let A = event where the the total of the numbers on the dices is greater than 10
Then the favourable outcomes are as follows:
A = {(5, 6), (6, 5), (6, 6)}
Number of favourable outcomes, n(A) = 3
Hence, required probability, P(A) = P (total of the numbers on the dices is greater than 10) = \[\frac{3}{36} = \frac{1}{12}\]
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