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Question
An urn contains twenty white slips of paper numbered from 1 through 20, ten red slips of paper numbered from 1 through 10, forty yellow slips of paper numbered from 1 through 40, and ten blue slips of paper numbered from 1 through 10. If these 80 slips of paper are thoroughly shuffled so that each slip has the same probability of being drawn. Find the probabilities of drawing a slip of paper that is numbered 1, 2, 3, 4 or 5
Solution
P(numbered 1, 2, 3, 4 or 5)
= P(1 of any colour) + P(2 of any colour) + P(3 of any colour) + P(4 of any colour) + P(5 of any colour)
= `4/80 + 4/80 + 4/80 + 4/80 + 4/80`
= `20/80`
= `2/8`
= `1/4`
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