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Question
A bag contains 8 red, 3 white and 9 blue balls. If three balls are drawn at random, determine the probability that all the three balls are blue balls
Solution
Out of 20 balls, three balls can be drawn in 20C3 ways.
∴ Total number of elementary events = 20C3
Out of nine blue balls, three blue balls can be chosen in 9C3 ways.
∴ Favourable number of events = 9C3 ways.
Hence, required probability = \[\frac{^{9}{}{C}_3}{^{20}{}{C}_3} = \frac{9 \times 8 \times 7}{20 \times 19 \times 18} = \frac{7}{95}\]
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