Advertisements
Advertisements
प्रश्न
In the expansion of (2x2 - 8) (x - 4)2; find the value of coefficient of x3.
बेरीज
उत्तर
( 2x2 - 8 )( x - 4 )2
= ( 2x2 - 8 )( x2 - 8x + 16 )
= 2x2( x2 - 8x + 16 ) - 8( x2 - 8x + 16 )
= 2x4 - 16x3 + 32x2 - 8x2 + 64x -128
= 2x4 - 16x3 + 24x2 + 64x - 128
Hence,
Coefficient of x3 = - 16
shaalaa.com
Expansion of Formula
या प्रश्नात किंवा उत्तरात काही त्रुटी आहे का?
APPEARS IN
संबंधित प्रश्न
Expand : `( 3a + 2/b )( 2a - 3/b )`
Expand : ( x + y - z )2
Expand : ( x - 2y + 2 )2
Expand : ( 5a - 3b + c )2
If a + `1/a` = m and a ≠ 0 ; find in terms of 'm'; the value of :
`a - 1/a`
If 2( x2 + 1 ) = 5x, find :
(i) `x - 1/x`
(ii) `x^3 - 1/x^3`
If a2 + b2 = 34 and ab = 12; find : 3(a + b)2 + 5(a - b)2
If `[x^2 + 1]/x = 3 1/3 "and x > 1; Find If" x - 1/x`
Find the value of 'a': 4x2 + ax + 9 = (2x - 3)2
If x = `1/( x - 5 ) "and x ≠ 5. Find" : x^2 - 1/x^2`
