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प्रश्न
In the given figure, AB is the diameter. The tangent at C meets AB produced at Q.
If ∠ CAB = 34° , find : ∠ CQB
उत्तर
QC is tangent to the circle
∴ ∠ CAB = ∠ QCB
Angle between tangent and chord = angle in alternate segment
∴ ∠ QCB = 34°
ABQ is a straight line
⇒ ∠ ABC + ∠ CBQ = 180°
⇒ 56° + ∠ CBQ = 180°
⇒ CBQ = 124°
Now,
∠ CQB = 180° - ∠ QCB = CBQ
⇒ ∠ CQB = 180° - 34°- 124°
⇒ ∠ CQB = 22°
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