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प्रश्न
उत्तर
Radius of the circle, r = 7 cm
m(arc MBN) = ∠MON = θ = 60º
Area of the sector =` theta/360 xx pir^2`
⇒ Area ( O - MBN ) =`60/360 `× Area of circle
Area of the sector = \[\frac{\theta}{360º} \times \pi r^2 = \frac{60º}{360º } \times \frac{22}{7} \times \left( 7 \right)^2\] = 25.7 cm2
⇒ A(O- MBN) = 25.7 sq. cm
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