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प्रश्न
Is the line 3x + 4y + 7 = 0 perpendicular to the line 28x – 21y + 50 = 0?
उत्तर
3x + 4y + 7 = 0
`=>` 4y = –3x – 7
`=> y = -3/4 xx -7/4`
Slope of this line = `(-3)/4`
28x – 21y + 50 = 0
`=>` 21y = 28x + 50
`=> y = 28/21x + 50/21`
`=> y = 4/3x + 50/21`
Slope of this line = `4/3`
Since, product of slopes of the two lines = –1, the lines are perpendicular to each other.
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