\[\lim_{x \to \infty} \left[ \frac{x^4 + 7 x^3 + 46x + a}{x^4 + 6} \right]\] where a is a non-zero real number.

\[\lim_{x \to \infty} \left[ \frac{x^4 + 7 x^3 + 46x + a}{x^4 + 6} \right]\] Dividing the numerator and the denominator by x4: \[\lim_{x \to \infty} \left[ \frac{1 + \frac{7}{x} + \frac{46}{x^2} + \frac{9}{x^4}}{1 + \frac{6}{x^4}} \right]\]\[\text{ As } x \to \infty , \frac{1}{x}, \frac{1}{x^2}, \frac{1}{x^3}, \frac{1}{x^4} \to 0\]\[ = \frac{1}{1}\]

Lim X → ∞ [ X 4 + 7 X 3 + 46 X + a X 4 + 6 ] Where a is a Non-zero Real Number. - Mathematics

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$lim_{x \to \infty} [\frac{x^{4} + 7 x^{3} + 46 x + a}{x^{4} + 6}]$ where a is a non-zero real number.

उत्तर

$lim_{x \to \infty} [\frac{x^{4} + 7 x^{3} + 46 x + a}{x^{4} + 6}]$ Dividing the numerator and the denominator by x⁴:

$lim_{x \to \infty} [\frac{1 + \frac{7}{x} + \frac{46}{x^{2}} + \frac{9}{x^{4}}}{1 + \frac{6}{x^{4}}}]$
$As x \to \infty, \frac{1}{x}, \frac{1}{x^{2}}, \frac{1}{x^{3}}, \frac{1}{x^{4}} \to 0$
$= \frac{1}{1}$

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Concept of Limits - Algebra of Limits

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Q 20 Q 19 Q 21

पाठ 29: Limits - Exercise 29.6 [पृष्ठ ३९]

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आरडी शर्मा Mathematics [English] Class 11

पाठ 29 Limits
Exercise 29.6 | Q 20 | पृष्ठ ३९

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Concept of Limits - Algebra of Limits

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Lim X → ∞ [ X 4 + 7 X 3 + 46 X + a X 4 + 6 ] Where a is a Non-zero Real Number. - Mathematics

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Lim X → ∞ [ X 4 + 7 X 3 + 46 X + a X 4 + 6 ] Where a is a Non-zero Real Number. - Mathematics

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