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प्रश्न
Reduce the following equation into intercept form and find their intercepts on the axes.
3x + 2y – 12 = 0
उत्तर
The given equation is 3x + 2y – 12 = 0.
It can be written as
3x + 2y – 12
`(3"x")/12 + (2"y")/12 = 1`
i.e. `"x"/4 + "y"/6 = 1` ..........(1)
This equation is of the form `"x"/"a" +"y"/"b" = 1`, where a = 4 and b = 6.
Therefore, equation (1) is in the intercept form, where the intercepts on the x and y axes are 4 and 6 respectively.
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