मराठी
महाराष्ट्र राज्य शिक्षण मंडळएस.एस.सी (इंग्रजी माध्यम) इयत्ता १० वी

Show that (x + 1) is a factor of the polynomial x3-x2-(2+2)x+2. - Algebra

Advertisements
Advertisements

प्रश्न

Show that (x + 1) is a factor of the polynomial `x^3 - x^2 - (2 + sqrt(2))x + sqrt(2)`.

बेरीज

उत्तर

Let p(x) = `x^3 - x^2 - (2 + sqrt(2))x + sqrt(2)`

By factor theorem, (x + 1) will be the factor of p(x) if p(– 1) = 0.

Now, p(– 1) = `(-1)^3 - (-1)^2 - (2 + sqrt(2)) (-1) + sqrt(2)`

= `-1 - 1 + 2 + sqrt(2) + sqrt(2)` 

= `2sqrt(2)`

∵ p(– 1) ≠ 0

Hence, (x + 1) is not a factor of p(x).

shaalaa.com
  या प्रश्नात किंवा उत्तरात काही त्रुटी आहे का?
2024-2025 (March) Model set 3 by shaalaa.com

संबंधित प्रश्‍न

If α and β are the roots of the quadratic equation `x^2 - 4x - 6 = 0`, find  the values of (i) `α^2+β^2` (ii) `α^3+β^3`

 


Form the quadratic equation if the roots are 3 and 8.


If one root of the quadratic, x2 - 7x + k = 0 is 4. then find the value of k.


Form the quadratic equation if its roots are 5 and 7. 


Solve the quadratic equation : 3x4 - 13x2 +10 = 0.


Convert the following equations into simultaneous equations and solve:

`sqrt("x"/"y") = 4, 1/"x" + 1/"y" = 1/"xy"`


Choose the correct alternative answer for the following sub-questions and write the correct alphabet.

Which of the following quadratic equation has roots – 3 and – 5?


If one of the roots of quadratic equation x2 + kx + 54 = 0 is – 6, then complete the following activity to find the value of ‘k’.

Activity: One of the roots of the quadratic equation x2 + kx + 54 = 0 is – 6.

Therefore let’s take x = ______

(– 6)2 + k(– 6) + 54 = 0

(______) – 6k + 54 = 0

– 6k + ______ = 0

k = ______


If the roots of a quadratic equation are 4 and – 5, then form the quadratic equation


Roots of a quadratic equation are 5 and – 4, then form the quadratic equation


Solve the following quadratic equations by formula method.

`y^2 + 1/3y` = 2


Sum of the roots of the quadratic equation is 5 and sum of their cubes is 35, then find the quadratic equation


Determine whether 2 is a root of quadratic equation 2m2 – 5m = 0.


One of the roots of equation kx2 – 10x + 3 = 0 is 3. Complete the following activity to find the value of k.

Activity:

One of the roots of equation kx2 – 10x + 3 = 0 is 3.

Putting x = `square` in the above equation

∴ `"k"(square)^2 - 10 xx square + 3` = 0

∴ `square` – 30 + 3 = 0

∴ 9k = `square`

∴ k = `square`


Determine whether (x – 3) is a factor of polynomial x3 – 19x + 30.

Let P(x) = x3 – 19x + 30

By remainder theorem, `square` will be a factor of P(x), if P(3) = 0

Now, P(3) = `square` – 19 `square` + 30

= `square  –  square` + 30

= `square  –  square`

= 0

∵ P(3) = 0

Hence, `square` is a factor of polynomial x3 – 19x + 30.


The value of the discriminant of the equation x2 + 6x – 15 = 0 is ______.


If x = `sqrt(7) - 2`, find the value of `(x + 1/x)`.


One of the roots of equation x2 + 5x + a = 0 is – 3. To find the value of a, fill in the boxes.

Since, `square` is a root of equation x2 + 5x + a = 0

∴ Put x = `square` in the equation

⇒ `square^2 + 5 xx square + a` = 0

⇒ `square + square + a` = 0

⇒ `square + a` = 0

⇒ a = `square`


If 3 is one of the roots of the quadratic equation kx2 − 7x + 12 = 0, then k = ______.


Share
Notifications

Englishहिंदीमराठी


      Forgot password?
Use app×