Advertisements
Advertisements
प्रश्न
If the roots of a quadratic equation are 4 and – 5, then form the quadratic equation
उत्तर
Let α = 4 and β = – 5
α + β = 4 – 5 = – 1
and α × β = 4 × (– 5) = – 20
∴ The required quadratic equation is
x2 – (α + β)x + αβ = 0
∴ x2 – (– 1) x + (– 20) = 0
∴ x2 + x – 20 = 0
APPEARS IN
संबंधित प्रश्न
Form the quadratic equation if the roots are 3 and 8.
Solve the quadratic equation : 3x4 - 13x2 +10 = 0.
Convert the following equations into simultaneous equations and solve:
`sqrt("x"/"y") = 4, 1/"x" + 1/"y" = 1/"xy"`
Choose the correct alternative answer for the following sub questions and write the correct alphabet.
Degree of quadratic equation is always ______
To decide whether 1 is a root of quadratic equation x2 + 4x – 5 = 0 or not, complete the following activity.
Activity: When x = (______)
L.H.S. = 12 + 4(______) – 5
= 1 + 4 – 5
= (______) – 5
= ______
= R.H.S
Therefore x = 1 is a root of quadratic equation x2 + 4x – 5 = 0
Roots of a quadratic equation are 5 and – 4, then form the quadratic equation
If the roots of the given quadratic equation are real and equal, then find the value of ‘k’
kx(x – 2) + 6 = 0
Solve the following quadratic equations by formula method.
5m2 – 4m – 2 = 0
Form a quadratic equation if the roots of the quadratic equation are `2 + sqrt(7)` and `2 - sqrt(7)`
Solve the following quadratic equation.
`1/(4 - "p") - 1/(2 + "p") = 1/4`
Determine whether 2 is a root of quadratic equation 2m2 – 5m = 0.
Solve the following quadratic equation using formula:
x2 + 10x + 2 = 0
If the sum of the roots of the quadratic equation x2 + kx + 6 = 0 is 6, then the value of k is ______.
The value of the discriminant of the equation x2 + 6x – 15 = 0 is ______.
Is (x – 5) a factor of the polynomial x3 – 5x – 30?
One of the roots of equation x2 + 5x + a = 0 is – 3. To find the value of a, fill in the boxes.
Since, `square` is a root of equation x2 + 5x + a = 0
∴ Put x = `square` in the equation
⇒ `square^2 + 5 xx square + a` = 0
⇒ `square + square + a` = 0
⇒ `square + a` = 0
⇒ a = `square`
