Question

Solve for 'θ': ${\displaystyle \sec (\frac{\theta }{2}+10°)=\frac{2}{\sqrt{3}}}$

Answer 1

${\displaystyle \sec (\frac{\theta }{2}+10°)=\frac{2}{\sqrt{3}}}$

⇒ ${\displaystyle \sec (\frac{\theta }{2}+10°)}$ = sec 30°

⇒ ${\displaystyle \frac{\theta }{2}+10°}$ = 30°

⇒ ${\displaystyle \frac{\theta }{2}}$ = 20°
⇒ θ = 40°.