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प्रश्न
Solve for 'θ': `sec(θ/2 + 10°) = (2)/sqrt(3)`
उत्तर
`sec(θ/2 + 10°) = (2)/sqrt(3)`
⇒ `sec(θ/2 + 10°)` = sec 30°
⇒ `θ/(2) + 10°` = 30°
⇒ `θ/(2)` = 20°
⇒ θ = 40°.
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