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प्रश्न
If θ < 90°, find the value of: `tan^2θ - (1)/cos^2θ`
उत्तर
Since θ <90°,
Consider θ = 45°
∴ `tan^2 θ - (1)/cos^2θ`
= `tan^2 45° - (1)/(cos^2 45°)`
= `(1)^2 - (1)/(1/sqrt(2))^2`
= `1 - (1)/(1/2)`
= 1 - 2
= -1.
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