Advertisements
Advertisements
प्रश्न
If `sqrt(3)`sec 2θ = 2 and θ< 90°, find the value of θ
योग
उत्तर
`sqrt(3)`sec 2θ = 2
⇒ sec2θ = `(2)/sqrt(3)`
⇒ sec2θ = sec30°
⇒ 2θ = 30°
⇒ θ =15°.
shaalaa.com
Trigonometric Equation Problem and Solution
क्या इस प्रश्न या उत्तर में कोई त्रुटि है?
APPEARS IN
संबंधित प्रश्न
If 4 sin2 θ - 1= 0 and angle θ is less than 90°, find the value of θ and hence the value of cos2 θ + tan2θ.
Solve the following equation for A, if 2cos2A = 1
Solve for x : cos `(x)/(3) –1` = 0
Solve for x : tan2 (x - 5°) = 3
Find the value of 'A', if 2 sin 2A = 1
In the given figure, PQ = 6 cm, RQ = x cm and RP = 10 cm, find
a. cosθ
b. sin2θ- cos2θ
c. Use tanθ to find the value of RQ
Find the value 'x', if:
Evaluate the following: `(tan12°)/(cot78°)`
Evaluate the following: cosec 54° - sec 36°
If secθ= cosec30° and θ is an acute angle, find the value of 4 sin2θ - 2 cos2θ.
