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प्रश्न
If `sqrt(3)` sec 2θ = 2 and θ< 90°, find the value of
cos 3θ
योग
उत्तर
`sqrt(3)`sec 2θ = 2
⇒ sec2θ = `(2)/sqrt(3)`
⇒ sec2θ = sec30°
⇒ 2θ = 30°
⇒ θ =15°
∴ cos3θ
= cos3 x 15°
= cos45°
= `(1)/sqrt(2)`.
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Trigonometric Equation Problem and Solution
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