Advertisements
Advertisements
प्रश्न
Solve for 'θ': `sin θ/(3)` = 1
उत्तर
`sin θ/(3)` = 1
⇒ `sin θ/(3)` = sin 90°
⇒ `θ/(3)` = 90°
⇒ θ = 270°.
APPEARS IN
संबंधित प्रश्न
If sin 3A = 1 and 0 < A < 90°, find sin A
If 2 cos 2A = `sqrt3` and A is acute,
find:
(i) A
(ii) sin 3A
(iii) sin2 (75° - A) + cos2 (45° +A)
Solve the following equation for A, if 2cos2A = 1
If sin 3A = 1 and 0 < A < 90°, find `tan^2A - (1)/(cos^2 "A")`
If `sqrt(2) = 1.414 and sqrt(3) = 1.732`, find the value of the following correct to two decimal places tan60°
If A = 30°, verify that cos2θ = `(1 - tan^2 θ)/(1 + tan^2 θ)` = cos4θ - sin4θ = 2cos2θ - 1 - 2sin2θ
In a right triangle ABC, right angled at C, if ∠B = 60° and AB = 15units, find the remaining angles and sides.
Evaluate the following: `(sin36°)/(cos54°) + (sec31°)/("cosec"59°)`
Prove the following: `(tan(90° - θ)cotθ)/("cosec"^2 θ)` = cos2θ
Prove the following: sin230° + cos230° = `(1)/(2)sec60°`