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प्रश्न
Solve the following equation.
6x − 1 = 3x + 8
उत्तर
6x − 1 = 3x + 8
⇒ 6x − 3x = 8 + 1
⇒ 3x = 9
⇒ x = `9/3`
⇒ x = 3
संबंधित प्रश्न
Express each of the following product as a monomials and verify the result in each case for x = 1:
(3x) × (4x) × (−5x)
Evaluate each of the following when x = 2, y = −1.
\[(2xy) \times \left( \frac{x^2 y}{4} \right) \times \left( x^2 \right) \times \left( y^2 \right)\]
Simplify: 3a2 + 2(a + 2) − 3a(2a + 1)
Simplify: a2(2a − 1) + 3a + a3 − 8
Find the following product and verify the result for x = − 1, y = − 2:
(x2y − 1) (3 − 2x2y)
Find the following product and verify the result for x = − 1, y = − 2: \[\left( \frac{1}{3}x - \frac{y^2}{5} \right)\left( \frac{1}{3}x + \frac{y^2}{5} \right)\]
Simplify:
(x3 − 2x2 + 5x − 7)(2x − 3)
Simplify:
(x2 − 3x + 2)(5x − 2) − (3x2 + 4x − 5)(2x − 1)
Show that: \[\left( \frac{4m}{3} - \frac{3n}{4} \right)^2 + 2mn = \frac{16 m^2}{9} + \frac{9 n^2}{16}\]
Show that: (4pq + 3q)2 − (4pq − 3q)2 = 48pq2
