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प्रश्न
Solve the following problem :
Given that `sum "p"_1"q"_1 = 300, sum "p"_0"q"_1 = 320, sum "p"_0"q"_0` = 120, and Marshall- Edgeworth’s Price Index Number is 120, find `sum"p"_1"q"_0` and Paasche’s Price Index Number.
उत्तर
Given, P01(M-E) = `120, sum "p"_1"q"_1 = 300, sum "p"_0"q"_1 = 320, sum "p"_0"q"_0 = 120`
P01(M–E) = `(sum"p"_1"q"_0 + sum"p"_1"q"_1)/(sum"p"_0"q"_0 + sum"p"_0"q"_1) xx 100`
∴ 120 = `(sum"p"_1"q"_0 + 300)/(120 + 320) xx 100`
∴ 120 = `(sum"p"_1"q"_0 + 300)/(440) xx 100`
∴ `sum"p"_1"q"_0 + 300 = (120 xx 440)/(100)`
∴ `sum"p"_1"q"_0 + 300` = 528
∴ `sum"p"_1"q"_0` = 528 – 300
∴ `sum"p"_1"q"_0` = 228
Paasche’s Price Index Number:
P01(P) = `(sum"p"_1"q"_1)/(sum"p"_0"q"_1) xx 100`
= `(300)/(320) xx 100`
= 93.75
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संबंधित प्रश्न
Calculate Laspeyre’s, Paasche’s, Dorbish-Bowley’s, and Marshall - Edgeworth’s Price index numbers.
Commodity | Base Year | Current Year | ||
Price | Quantity | Price | Quantity | |
I | 10 | 9 | 20 | 8 |
II | 20 | 5 | 30 | 4 |
III | 30 | 7 | 50 | 5 |
IV | 40 | 8 | 60 | 6 |
Calculate Walsh’s Price Index Number.
Commodity | Base Year | Current Year | ||
Price | Quantity | Price | Quantity | |
I | 10 | 12 | 20 | 9 |
II | 20 | 4 | 25 | 8 |
III | 30 | 13 | 40 | 27 |
IV | 60 | 29 | 75 | 36 |
Choose the correct alternative :
The price Index Number by Weighted Aggregate Method is given by ______.
Dorbish-Bowley’s Price Index Number is given by ______.
State whether the following is True or False :
`(sum"p"_1"q"_0)/(sum"p"_0"q"_0) xx (sum"p"_1"q"_0)/(sum"p"_0"q"_0) xx 100` is Dorbish-Bowley’s Price Index Number.
State whether the following is True or False :
`sqrt(("p"_1"q"_0)/(sum"p"_0"q"_0)) xx sqrt((sum"p"_1"q"_1)/(sum"p"_0"q"_1)) xx 100` is Fisher’s Price Index Number.
Solve the following problem :
Calculate Laspeyre’s and Paasche’s Price Index Number for the following data.
Commodity | Base year | Current year | ||
Price p0 |
Quantity q0 |
price p1 |
Quantity q1 |
|
A | 20 | 18 | 30 | 15 |
B | 25 | 8 | 28 | 5 |
C | 32 | 5 | 40 | 7 |
D | 12 | 10 | 18 | 10 |
Solve the following problem :
Calculate Dorbish-Bowley’s Price Index Number for the following data.
Commodity | Base Year | Current Year | ||
Price p0 |
Quantity q0 |
Price p1 |
Quantity q1 |
|
I | 8 | 30 | 11 | 28 |
II | 9 | 25 | 12 | 22 |
III | 10 | 15 | 13 | 11 |
Solve the following problem :
Calculate Walsh’s Price Index Number for the following data.
Commodity | Base year | Current year | ||
Price p0 |
Quantity q0 |
Price p1 |
Quantity q1 |
|
I | 8 | 30 | 12 | 25 |
II | 10 | 42 | 20 | 16 |
Solve the following problem :
Given that `sum "p"_0"q"_0 = 130, sum "p"_1"q"_1 = 140, sum "p"_0"q"_1 = 160, and sum "p"_1"q"_0 = 200`, find Laspeyre’s, Paasche’s, Dorbish-Bowley’s, and Marshall-Edgeworth’s Price Index Numbers.
Choose the correct alternative:
The formula P01 = `(sum"p"_1"q"_0)/(sum"p"_0"q"_0) xx 100` is for
State whether the following statement is True or False:
`(sum"p"_0sqrt("q"_0 + "q"_1))/(sum"p"_1sqrt("q"_0 + "q"_1)) xx 100` is Marshall-Edgeworth Price Index Number
Calculate Marshall-Edgeworth Price Index Number for following.
Commodity | Base Year | Current Year | ||
Price | Quantity | Price | Quantity | |
A | 8 | 20 | 11 | 15 |
B | 7 | 10 | 12 | 10 |
C | 3 | 30 | 5 | 25 |
D | 2 | 50 | 4 | 35 |
If P01(L) = 40 and P01(P) = 90, find P01(D-B) and P01(F).
Find the missing price if Laspeyre’s and Paasche’s Price Index Numbers are equal for following data.
Commodity | Base Year | Current Year | ||
Price | Quantity | Price | Quantity | |
A | 1 | 10 | 2 | 5 |
B | 1 | 5 | – | 12 |
`sqrt((sump_1q_0)/(sump_0q_0)) xx sqrt((sump_1q_1)/(sump_0q_1)) xx 100`
Calculate Marshall – Edgeworth’s price index number for the following data:
Commodity | Base year | Current year | ||
Price | Quantity | Price | Quantity | |
P | 12 | 20 | 18 | 24 |
Q | 14 | 12 | 21 | 16 |
R | 8 | 10 | 12 | 18 |
S | 16 | 15 | 20 | 25 |
In the following table, Laspeyre's and Paasche's Price Index Numbers are equal. Complete the following activity to find x :
Commodity | Base Year | Current year | ||
Price | Quantity | Price | Quantity | |
A | 2 | 10 | 2 | 5 |
B | 2 | 5 | x | 2 |
Solution: P01(L) = P01(P)
`(sum "p"_1"q"_0)/(sum "p"_0"q"_0) xx 100 = square/(sum "p"_0"q"_1) xx 100`
`(20 + 5x)/square xx 100 = square/14 xx 100`
∴ x = `square`