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State the Basic Proportionality Theorem. - Mathematics

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प्रश्न

State the basic proportionality theorem. 

 

उत्तर

If a line is draw parallel to one side of a triangle intersect the other two sides, then it divides the other two sides in the same ratio. 

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पाठ 4: Triangles - Exercises 5

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In the given figure, PS is the bisector of ∠QPR of ΔPQR. Prove that `(QS)/(SR) = (PQ)/(PR)`


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A line is parallel to one side of triangle which intersects remaining two sides in two distinct points then that line divides sides in same proportion.

Given: In ΔABC line l || side BC and line l intersect side AB in P and side AC in Q.

To prove: `"AP"/"PB" = "AQ"/"QC"`

Construction: Draw CP and BQ

Proof: ΔAPQ and ΔPQB have equal height.

`("A"(Δ"APQ"))/("A"(Δ"PQB")) = (["______"])/"PB"`   .....(i)[areas in proportion of base]

`("A"(Δ"APQ"))/("A"(Δ"PQC")) = (["______"])/"QC"`  .......(ii)[areas in proportion of base]

ΔPQC and ΔPQB have [______] is common base.

Seg PQ || Seg BC, hence height of ΔAPQ and ΔPQB.

A(ΔPQC) = A(Δ______)    ......(iii)

`("A"(Δ"APQ"))/("A"(Δ"PQB")) = ("A"(Δ "______"))/("A"(Δ "______"))`   ......[(i), (ii), and (iii)]

`"AP"/"PB" = "AQ"/"QC"`   .......[(i) and (ii)]


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