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State conservation of angular momentum. - Physics

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प्रश्न

State conservation of angular momentum.

टीपा लिहा

उत्तर

The law of conservation of angular momentum states that when no external torque acts on the body the net angular momentum of a rotating rigid body remains constant.

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  या प्रश्नात किंवा उत्तरात काही त्रुटी आहे का?
पाठ 5: Motion of System of Particles and Rigid Bodies - Evaluation [पृष्ठ २६२]

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सामाचीर कलवी Physics - Volume 1 and 2 [English] Class 11 TN Board
पाठ 5 Motion of System of Particles and Rigid Bodies
Evaluation | Q II. 14. | पृष्ठ २६२

संबंधित प्रश्‍न

Find the components along the x, y, z axes of the angular momentum of a particle, whose position vector is with components x, y, z and momentum is with components px, py and 'p_z`. Show that if the particle moves only in the x-y plane the angular momentum has only a z-component.


The torque of the weight of any body about any vertical axis is zero. If it always correct?


The torque of a force \[\overrightarrow F \] about a point is defined as \[\overrightarrow\Gamma  =  \overrightarrow r  \times  \overrightarrow F.\] Suppose \[\overrightarrow r, \overrightarrow F\] and \[\overrightarrow \Gamma\] are all nonzero. Is \[r \times  \overrightarrow\Gamma || \overrightarrow F\] always true? Is it ever true?


A uniform cube of mass m and side a is placed on a frictionless horizontal surface. A vertical force F is applied to the edge as shown in figure. Match the following (most appropriate choice):

(a) mg/4 < F < mg/2 (i) Cube will move up.
(b) F > mg/2 (ii) Cube will not exhibit motion.
(c) F > mg (iii) Cube will begin to rotate and slip at A.
(d) F = mg/4 (iv) Normal reaction effectively at a/3 from A, no motion.

A uniform sphere of mass m and radius R is placed on a rough horizontal surface (Figure). The sphere is struck horizontally at a height h from the floor. Match the following:

Column I Column II
(a) h = R/2 (i) Sphere rolls without slipping with a constant velocity and no loss of energy.
(b) h = R (ii) Sphere spins clockwise, loses energy by friction.
(c) h = 3R/2 (iii) Sphere spins anti-clockwise, loses energy by friction.
(d) h = 7R/5 (iv) Sphere has only a translational motion, looses energy by friction.

A door is hinged at one end and is free to rotate about a vertical axis (Figure). Does its weight cause any torque about this axis? Give reason for your answer.


Two discs of moments of inertia I1 and I2 about their respective axes (normal to the disc and passing through the centre), and rotating with angular speed ω2 and ω2 are brought into contact face to face with their axes of rotation coincident.

  1. Does the law of conservation of angular momentum apply to the situation? why?
  2. Find the angular speed of the two-disc system.
  3. Calculate the loss in kinetic energy of the system in the process.
  4. Account for this loss.

A rod of mass 'm' hinged at one end is free to rotate in a horizontal plane. A small bullet of mass m/4 travelling with speed 'u' hits the rod and attaches to it at its centre. Find the angular speed of rotation of rod just after the bullet hits the rod 3. [take length of the rod as 'l']


The position vector of 1 kg object is `vecr = (3hati - hatj)` m and its velocity `vecv = (3hati + hatk)` ms-1. The magnitude of its angular momentum is `sqrtx` Nm where x is ______.


Angular momentum of a single particle moving with constant speed along the circular path ______.


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