मराठी

The given figure shows a pentagon ABCDE. EG drawn parallel to DA meets BA produced at G and CF draw parallel to DB meets AB produced at F. - Mathematics

Advertisements
Advertisements

प्रश्न

The given figure shows a pentagon ABCDE. EG drawn parallel to DA meets BA produced at G and CF draw parallel to DB meets AB produced at F.

Prove that the area of pentagon ABCDE is equal to the area of triangle GDF.

बेरीज

उत्तर


Since triangle EDG and EGA are on the same base EG and between the same parallel lines EG and DA.

Therefore,

A(ΔEDG) = A(ΔEGA)

Subtracting ΔEOG from both sides, we have

A(ΔEOD) = A(ΔGOA)              ...(i)

Similarly,

A(ΔDPC) = A(ΔBPF)              ...(ii)

Now

A(ΔGDF) = A(ΔGOA) + A(ΔBPF) + A(pen. ABPDO) 

= A(ΔEOD) + A(ΔDPC) + A(pen. ABPDO)

= A(pen. ABCDE)

Hence, proved.

shaalaa.com
Figures Between the Same Parallels
  या प्रश्नात किंवा उत्तरात काही त्रुटी आहे का?
पाठ 16: Area Theorems [Proof and Use] - Exercise 16 (A) [पृष्ठ १९७]

APPEARS IN

सेलिना Concise Mathematics [English] Class 9 ICSE
पाठ 16 Area Theorems [Proof and Use]
Exercise 16 (A) | Q 8 | पृष्ठ १९७

संबंधित प्रश्‍न

The given figure shows the parallelograms ABCD and APQR.
Show that these parallelograms are equal in the area.
[ Join B and R ]


In the given figure, ABCD is a parallelogram; BC is produced to point X.
Prove that: area ( Δ ABX ) = area (`square`ACXD )


ABCD is a trapezium with AB // DC. A line parallel to AC intersects AB at point M and BC at point N.
Prove that: area of Δ ADM = area of Δ ACN.


In parallelogram ABCD, P is a point on side AB and Q is a point on side BC.
Prove that:
(i) ΔCPD and ΔAQD are equal in the area.
(ii) Area (ΔAQD) = Area (ΔAPD) + Area (ΔCPB)


In the given figure, M and N are the mid-points of the sides DC and AB respectively of the parallelogram ABCD.

If the area of parallelogram ABCD is 48 cm2;
(i) State the area of the triangle BEC.
(ii) Name the parallelogram which is equal in area to the triangle BEC.


In the figure given alongside, squares ABDE and AFGC are drawn on the side AB and the hypotenuse AC of the right triangle ABC.

If BH is perpendicular to FG

prove that:

  1. ΔEAC ≅ ΔBAF
  2. Area of the square ABDE
  3. Area of the rectangle ARHF.

Show that:

A diagonal divides a parallelogram into two triangles of equal area.


ABCD is a trapezium with AB parallel to DC. A line parallel to AC intersects AB at X and BC at Y.
Prove that the area of ∆ADX = area of ∆ACY.


E, F, G, and H are the midpoints of the sides of a parallelogram ABCD.
Show that the area of quadrilateral EFGH is half of the area of parallelogram ABCD.


In parallelogram ABCD, E is a point in AB and DE meets diagonal AC at point F. If DF: FE = 5:3 and area of  ΔADF is 60 cm2; find
(i) area of ΔADE.
(ii) if AE: EB = 4:5, find the area of  ΔADB.
(iii) also, find the area of parallelogram ABCD.


Share
Notifications

Englishहिंदीमराठी


      Forgot password?
Use app×