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प्रश्न
The magnetic flux through a loop varies according to the relation Φ = 8t2 + 6t + C, where ‘C’ is constant, 'Φ' is in milliweber and 't' is in second. What is the magnitude of induced e.m.f. in the loop at t = 2 seconds.
उत्तर
Magnetic flux through the coil is given by relation
Φ = 8t2 + 6t + c (where c is constant) (i)
To find the magnitude of the induced e.m.f. ‘e’ in the loop at t = 2 seconds, we know that `e=|(dphi)/dt|`
Differentiating equation (i) w.r.t. t we get,
e = 16t + 6
e = 16 × (2) + 6
e = 38 millivolt = 0.038 volt
Hence, the magnitude of induced e.m.f. is 0.038 volt.
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