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The Shadow of a Tower, When the Angle of Elevation of the Sun is 45°, is Found to Be 10 M. Longer than When It Was 600. Find the Height of the Tower. - Mathematics

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प्रश्न

The shadow of a tower, when the angle of elevation of the sun is 45°, is found to be 10 m. longer than when it was 600. Find the height of the tower.

उत्तर

Let h be the height of tower AB and angle of elevation are 45° and 60° are given.

In a triangle OAC, given that AB = 10+x and BC x

Now we have to find the height of the tower.

So we use trigonometrical ratios.

In a triangle OAB,

`=> tan A = (OB)/(AB)`

`=> tan 45^@ = (OB)/(AB)`

`=> 1= h/(10 + x)`

=> h = 10 + x

Therefore  x = h - 10

Again in a triangle OCB

`=> tan C = (OB)/(BC)`

`=> tan 60^@ = (OB)/(BC)`

`=> sqrt3 = h/x`

`=> h = sqrt3x`

Put x = h - 10

`=> h = sqrt3 (h - 10)`

`=> h = sqrt3h - 10sqrt3`

`=> 10sqrt3 = h(sqrt3 - 1)`

`=> h = (10sqrt3)/(sqrt3 - 1)`

`=>  h = (10 xx 1.732)/(1.732 - 1)`

`=> h = 17.32/0.327`

=> h = 23.66

Hence height of tower is 23.66 m

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पाठ 12: Trigonometry - Exercise 12.1 [पृष्ठ ३०]

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आरडी शर्मा Mathematics [English] Class 10
पाठ 12 Trigonometry
Exercise 12.1 | Q 11 | पृष्ठ ३०

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