Advertisements
Advertisements
प्रश्न
Trapezium given below; find its area.
उत्तर
Area of ΔEBC = `1/4 xx 8 xx sqrt( 4 xx 10^2 - 8^2 )`
= `1/4 xx 8 xx 18.3`
= 36.6 cm2
Again
Area of ΔEBC = `1/2` x 8 x h
36.6 = 4h
h = 9.15
Area of ABCD = `1/2 xx ( 12 + 20 ) xx 9.15`
= `1/2` x 32 x 9.15
= 146.64 sq.cm
APPEARS IN
संबंधित प्रश्न
The diagonal of a quadrilateral shaped field is 24 m and the perpendiculars dropped on it from the remaining opposite vertices are 8 m and 13 m. Find the area of the field.
Diagram of the adjacent picture frame has outer dimensions = 24 cm × 28 cm and inner dimensions 16 cm × 20 cm. Find the area of each section of the frame, if the width of each section is same.
ABCD is a square with each side 12 cm. P is a point on BC such that area of ΔABP: area of trapezium APCD = 1: 5. Find the length of CP.
Trapezium given below; find its area.
A wire when bent in the form of a square encloses an area of 484 m2. Find the largest area enclosed by the same wire when bent to from:
- An equilateral triangle.
- A rectangle of length 16 m.
Calculate the area of the figure given below: which is not drawn scale.
The area of a rhombus is 216 sq. cm. If it's one diagonal is 24 cm; find:
(i) Length of its other diagonal,
(ii) Length of its side,
(iii) The perimeter of the rhombus.
The floor of a room is of size 6 m x 5 m. Find the cost of covering the floor of the room with 50 cm wide carpet at the rate of Rs.24.50 per metre. Also, find the cost of carpeting the same hall if the carpet, 60 cm, wide, is at the rate of Rs.26 per metre.
Find the area of a quadrilateral field whose sides are 12m, 9m, 18m and 21m respectively and the angle between the first two sides is a right angle. Take the value of `sqrt(6)` as 2.5.
The quadrilateral swimming pool shown is surrounded by concrete patio. Find the area of the patio
