Advertisements
Advertisements
प्रश्न
Two chords AB and CD of a circle are each at distances 4 cm from the centre. Then AB = CD.
पर्याय
True
False
उत्तर
This statement is True.
Explanation:
Because, the chords equidistant from the centre of circle are equal in length.
APPEARS IN
संबंधित प्रश्न
Two circles of radii 5 cm and 3 cm intersect at two points and the distance between their centres is 4 cm. Find the length of the common chord.
If two equal chords of a circle intersect within the circle, prove that the line joining the point of intersection to the centre makes equal angles with the chords.
If a line intersects two concentric circles (circles with the same centre) with centre O at A, B, C, and D, prove that AB = CD (see given figure).
true or false
If a circle is divided into three equal arcs each is a major arc.
true or false
A circle has only finite number of equal chords.
An equilateral triangle of side 9cm is inscribed in a circle. Find the radius of the circle.
Two chords AB and CD of lengths 5 cm and 11 cm respectively of a circle are parallel to each other and are opposite side of its center. If the distance between AB and CD is 6 cm. Find the radius of the circle.
Angle formed in minor segment of a circle is
If AB is a chord of a circle, P and Q are the two points on the circle different from A and B, then
AB and AC are two chords of a circle of radius r such that AB = 2AC. If p and q are the distances of AB and AC from the centre, prove that 4q2 = p2 + 3r2.