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कर्नाटक बोर्ड पी.यू.सी.पीयूसी विज्ञान 2nd PUC Class 12

Which of the following compounds would undergo aldol condensation, which the Cannizzaro reaction and which neither? Write the structures of the expected products of aldol condensation - Chemistry

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प्रश्न

Which of the following compounds would undergo aldol condensation, which the Cannizzaro reaction and which neither? Write the structures of the expected products of aldol condensation and Cannizzaro reaction.

  1. Methanal
  2. 2-Methylpentanal
  3. Benzaldehyde
  4. Benzophenone
  5. Cyclohexanone
  6. 1-Phenylpropanone
  7. Phenylacetaldehyde
  8. Butan-1-ol
  9. 2, 2-Dimethylbutanal
रासायनिक समीकरणे/रचना
दीर्घउत्तर

उत्तर

Aldehydes and ketones having at least one α-hydrogen undergo aldol condensation.

The compounds (ii) 2-Methylpentanal, (v) Cyclohexanone, (vi) 1-phenylpropanone, and (vii) Phenylacetaldehyde contain one or more α-hydrogen atoms. Therefore, these undergo aldol condensation.

Aldehydes having no α-hydrogen atoms undergo Cannizzaro reactions. The compounds (i) Methanal, (iii) Benzaldehyde, and (ix) 2, 2-dimethylbutanal do not have any α-hydrogen. Therefore, these undergo cannizzaro reactions.

Compound (iv) Benzophenone is a ketone having no α-hydrogen atom and compound (viii) Butan-1-ol is an alcohol. Hence, these compounds do not undergo either aldol condensation or cannizzaro reactions.

Aldol condensation:

(ii)

\[\begin{array}{cc}
\phantom{...................................................}\ce{CH3}\\
\phantom{................................................}|\\
\ce{2CH3CH2CH2 - CH - CHO ->[dil NaOH] CH3CH2CH2 - CH - CH - CH - CH2CH2CH3}\\
|\phantom{...................................}|\phantom{......}|\phantom{......}|\phantom{}\\
\phantom{......}\ce{\underset{2-Methylpentanal}{CH3}}\phantom{....................}\ce{\underset{3-Hydroxy-2,4-dimethyl-2-propylheptanal}{\phantom{..}CH3\phantom{...}OH\phantom{...}CHO}}
\end{array}\]

(v)

(vi)

(vii)

Cannizzaro reaction:

(i)
\[\begin{array}{cc}
\ce{H}\phantom{..............................}\ce{H}\phantom{.......}\ce{H}\phantom{......}\\
\backslash\phantom{..............................}|\phantom{.........}\backslash\phantom{....}\\
\ce{2\phantom{...}C = O + conc.KOH -> H - C - OH + C - OK}\\
/\phantom{..............................}|\phantom{.........}/\phantom{....}\\
\ce{\underset{Methanal}{H}}\phantom{..........................}\ce{\underset{Methanol}{H}}\phantom{.}\ce{\underset{methanoate}{\underset{Potassim}{H}}}\phantom{......}
\end{array}\]
(iii)

(ix)

\[\begin{array}{cc}
\phantom{.....}\ce{CH3}\phantom{............................}\ce{CH3}\phantom{........................}\ce{CH3}\phantom{...}\\
\phantom{}|\phantom{...............................}|\phantom{............................}|\phantom{.}\\
\ce{CH3CH2 - C - CHO ->[conc. NaOH] CH3CH2 - C - CH2 - OH + CH3CH2 - C - C - ONa}\\
\phantom{.....}|\phantom{...............................}|\phantom{............................}|\phantom{....}||\phantom{}\\
\phantom{.........}\ce{\underset{2, 2-Dimethylbutanal}{CH3}}\phantom{...............}\ce{\underset{2, 2-Dimethylbutan-1-ol}{CH3}}\phantom{..........}\ce{\underset{Sodium 2, 2-dimethylbutanoate}{CH3\phantom{.}O}}\phantom{.}
\end{array}\]

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पाठ 12: Aldehydes, Ketones and Carboxylic Acids - Exercises [पृष्ठ ३७८]

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एनसीईआरटी Chemistry [English] Class 12
पाठ 12 Aldehydes, Ketones and Carboxylic Acids
Exercises | Q 7 | पृष्ठ ३७८

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Aldol


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\[\begin{array}{cc}
\ce{C6H5CHO}\phantom{............}\\
\phantom{........}\ce{+\phantom{......}\ce{->[dil.NaOH][\Delta]}}\phantom{...}\\
\ce{CH3CH2CHO}\phantom{............}
\end{array}\]


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(i) \[\ce{CH3 - CHO}\]

(ii)  

(iii)  \[\begin{array}{cc}
\phantom{}\ce{O}\\
\phantom{}||\\
\ce{CH3 - C - CH3}
\end{array}\]

(iv) \[\begin{array}{cc}
\phantom{}\ce{CH3}\\
|\phantom{...}\\
\ce{CH3 - C - CHO}\phantom{..}\\
|\phantom{...}\\
\phantom{}\ce{CH3}\\
\end{array}\]


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Acetaldehyde to But-2-enal


\[\ce{CH3-CH2-CHO ->[dil][alkali] Product}\]

The product in the above reaction is:


The major product of the following reaction is:


When acetaldehyde is treated with dilute NaOH, the following reaction is observed.

\[\begin{array}{cc}
\ce{2CH3 - CHO ->[dil.NaOH] CH3 - CH - CH2 - CHO}\\
\phantom{...............}|\\
\phantom{.................}\ce{OH}
\end{array}\]

  1. What are the functional groups in the product?
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Write a note on the aldol condensation reaction of acetaldehyde.


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