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Question
3x − 7 > x + 1
Solution
\[3x - 7 > x + 1\]
\[ \Rightarrow 3x - x > 1 + 7 \left( \text{ Transposing x to LHS and - 7 to RHS } \right)\]
\[ \Rightarrow 2x > 8\]
\[ \Rightarrow x > 4 \left( \text{ Dividing both sides by 2 } \right)\]
\[\text{ Hence, the solution set of the given inequation is } \left( 4, \infty \right)\]
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