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Question
A bucket is in the form of a frustum of a cone and holds 15.25 litres of water. The diameters of the top and bottom are 25 cm and 20 cm respectively. Find its height and area of tin used in its construction.
Solution
Since volume of frustum
`=(pih)/3 (R^2 +Rr +r^2)`
`= 15250 cm^3`
`h xx pi/3 xx ((25/2)^2 + (10)^2 + 25/2 xx 10)`
`=15250`
`h xx pi/3(156.25 + 22.5)`
`=15250`
`h = (3 xx 7 xx 15250)/(22 xx 381.25)`
`=(320250)/(8387.5)`
= 38.18 cm
Area of the required
`= pi (12.5 + 10)sqrt((12.5 - 10) + 38.18)`
`=3017 cm^2`
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