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Karnataka Board PUCPUC Science Class 11

A Double Slit S1 − S2 is Illuminated by a Coherent Light of Wavelength λ . the Slits Are Separated by a Distance D. - Physics

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Question

A double slit S1 − S2 is illuminated by a coherent light of wavelength \[\lambda.\] The slits are separated by a distance d. A plane mirror is placed in front of the double slit at a distance D1 from it and a screen ∑ is placed behind the double slit at a distance D2 from it (see the following figure). The screen ∑ receives only the light reflected by the mirror. Find the fringe-width of the interference pattern on the screen.

Sum

Solution

Given:-

Separation between the two slits = d

Wavelength of the coherent light =λ

Distance between the slit and mirror is D1.

Distance between the slit and screen is D2.

Therefore,

apparent distance of the screen from the slits,

\[D = 2 D_1 + D_2 \]

Fringe width, \[\beta = \frac{\lambda D}{d} = \frac{\left( 2 D_1 + D_2 \right) \lambda}{d}\]

Hence, the required fringe width is \[\frac{\left( 2 D_1 + D_2 \right)  \lambda}{d}.\]

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Chapter 17: Light Waves - Exercise [Page 382]

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HC Verma Concepts of Physics Vol. 1 [English] Class 11 and 12
Chapter 17 Light Waves
Exercise | Q 24 | Page 382

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