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Question
A line passes through P(1, 2) such that its intercept between the axes is bisected at P. The equation of the line is ______.
Options
x + 2y = 5
x – y + 1 = 0
x + y – 3 = 0
2x + y – 4 = 0
Solution
A line passes through P(1, 2) such that its intercept between the axes is bisected at P. The equation of the line is 2x + y – 4 = 0.
Explanation:
We know that the equation of a line making intercepts a and b with x-axis and y-axis, respectively, is given by
`x/a + y/b` = 1.
Here we have 1 = `(a + 0)/2` and 2 = `(0 + b)/2`.
Which give a = 2 and b = 4.
Therefore, the required equation of the line is given by
`x/2 + y/4` = 1 or 2x + y – 4 = 0
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