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Question
Find the equation of a line which makes an angle of tan−1 (3) with the x-axis and cuts off an intercept of 4 units on negative direction of y-axis.
Solution
Let m be the slope of the required line.
\[\therefore m = \tan\theta = \tan\left\{ \tan^{- 1} \left( 3 \right) \right\} = 3\]
\[ c = y - \text { intercept } = - 4\]
Substituting the values of m and c in y = mx + c, we get y = 3x -4
Hence, the equation of the required line is y = 3x - 4
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