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Question
Reduce the following equation into intercept form and find their intercepts on the axes.
3y + 2 = 0
Solution
The given equation is 3y + 2 = 0.
It can be written as
3y = −2
i.e., `"y"/((- 2/3)) = 1` ...........(1)
This equation is of the form `"x"/"a" + "y"/"b" = 1`, where a = 0 and b = `−2/3`.
Therefore, equation (1) is in the intercept form, where the intercepts on the y-axis is `-2/3` and it has no intercept on the x-axis.
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