Question

Reduce the following equation into intercept form and find their intercepts on the axes.

3y + 2 = 0

Answer 1

The given equation is 3y + 2 = 0.

It can be written as

3y = −2

i.e., ${\displaystyle \frac{\text{y}}{(-\frac{2}{3})}=1}$ ...........(1)

This equation is of the form ${\displaystyle \frac{\text{x}}{\text{a}}+\frac{\text{y}}{\text{b}}=1}$, where a = 0 and b = ${\displaystyle -\frac{2}{3}}$.

Therefore, equation (1) is in the intercept form, where the intercepts on the y-axis is ${\displaystyle -\frac{2}{3}}$ and it has no intercept on the x-axis.