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A Random Variable Has the Following Probability Distribution:X = Xi :1234p (X = Xi) :K2k3k4kwrite the Value Of P (X ≥ 3). - Mathematics

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Question

A random variable has the following probability distribution: 

X = xi : 1 2 3 4
P (X = xi) : k 2k 3k 4k

Write the value of P (X ≥ 3).

 
Sum

Solution

We know that the sum of probabilities in a probability distribution is always 1.

∴ P (X = 1) + P (X = 2) + P (X = 3) + P (X = 4) = 1

\[\Rightarrow k + 2k + 3k + 4k = 1\]
\[ \Rightarrow 10k = 1\]
\[ \Rightarrow k = \frac{1}{10}\]
\[\text{ Now} , \]
\[P\left( X \geq 3 \right) = P\left( X = 3 \right) + P\left( X = 4 \right) = \frac{3}{10} + \frac{4}{10} = \frac{7}{10}\]

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Chapter 32: Mean and Variance of a Random Variable - Very Short Answers [Page 45]

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RD Sharma Mathematics [English] Class 12
Chapter 32 Mean and Variance of a Random Variable
Very Short Answers | Q 7 | Page 45

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