English

A Time Period of a Particle in Shm Depends on the Force Constant K And Mass M Of the Particle: `T = 2pi Sqrt(M/K)` A Simple Pendulum Executes Shm Approximately. Why Then is the Time - Physics

Advertisements
Advertisements

Question

Answer the following questions:

A time period of a particle in SHM depends on the force constant and mass of the particle: `T = 2pi sqrt(m/k)` A simple pendulum executes SHM approximately. Why then is the time 

 

Solution 1

The time period of a simple pendulum, `T = 2pi sqrt(m/k)`

For a simple pendulum, k is expressed in terms of mass m, as: `k prop m` 

`m/k =` Constant

Hence, the time period T, of a simple pendulum is independent of the mass of the bob.

 

shaalaa.com

Solution 2

In case of a spring, k does not depend upon m. However, in case of a simple pendulum, k is directly proportional to m and hence the ratio m/k is constant quantity

shaalaa.com
  Is there an error in this question or solution?
Chapter 14: Oscillations - Exercises [Page 360]

APPEARS IN

NCERT Physics [English] Class 11
Chapter 14 Oscillations
Exercises | Q 16.1 | Page 360

Video TutorialsVIEW ALL [1]

RELATED QUESTIONS

If the metal bob of a simple pendulum is replaced by a wooden bob of the same size, then its time period will.....................

  1. increase
  2. remain same
  3. decrease
  4. first increase and then decrease.

The phase difference between displacement and acceleration of a particle performing S.H.M. is _______.

(A) `pi/2rad`

(B) π rad

(C) 2π rad

(D)`(3pi)/2rad`


A spring having with a spring constant 1200 N m–1 is mounted on a horizontal table as shown in Fig. A mass of 3 kg is attached to the free end of the spring. The mass is then pulled sideways to a distance of 2.0 cm and released.

Determine (i) the frequency of oscillations, (ii) maximum acceleration of the mass, and (iii) the maximum speed of the mass.


The cylindrical piece of the cork of density of base area and height floats in a liquid of density `rho_1`. The cork is depressed slightly and then released. Show that the cork oscillates up and down simple harmonically with a period

`T = 2pi sqrt((hrho)/(rho_1g)` 

where ρ is the density of cork. (Ignore damping due to viscosity of the liquid).


A clock regulated by seconds pendulum, keeps correct time. During summer, length of pendulum increases to 1.005 m. How much will the clock gain or loose in one day?

(g = 9.8 m/s2 and π = 3.142)


A simple pendulum has a time period of T1 when on the earth's surface and T2 when taken to a height R above the earth's surface, where R is the radius of the earth. The value of `"T"_2 // "T"_1` is ______. 


The period of oscillation of a simple pendulum of constant length at the surface of the earth is T. Its time period inside mine will be ______.


Two identical springs of spring constant K are attached to a block of mass m and to fixed supports as shown in figure. When the mass is displaced from equilibrium position by a distance x towards right, find the restoring force


Consider a pair of identical pendulums, which oscillate with equal amplitude independently such that when one pendulum is at its extreme position making an angle of 2° to the right with the vertical, the other pendulum makes an angle of 1° to the left of the vertical. What is the phase difference between the pendulums?


A simple pendulum of time period 1s and length l is hung from a fixed support at O, such that the bob is at a distance H vertically above A on the ground (Figure). The amplitude is θ0. The string snaps at θ = θ0/2. Find the time taken by the bob to hit the ground. Also find distance from A where bob hits the ground. Assume θo to be small so that sin θo = θo and cos θo = 1.


Share
Notifications

Englishहिंदीमराठी


      Forgot password?
Use app×